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x=100x-0.5x^2
We move all terms to the left:
x-(100x-0.5x^2)=0
We get rid of parentheses
0.5x^2-100x+x=0
We add all the numbers together, and all the variables
0.5x^2-99x=0
a = 0.5; b = -99; c = 0;
Δ = b2-4ac
Δ = -992-4·0.5·0
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9801}=99$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-99}{2*0.5}=\frac{0}{1} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+99}{2*0.5}=\frac{198}{1} =198 $
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